Question

when i need to solve a polynomial equation like :
(x^2+7x^2-2x-14)(x^3+x^2+2x+2)=0
do i need to factor both sides then do long division or what.. ???

Answer 1

i think you can just divide one of the polynomials to both sides so you only deal with one of them

Answer 2

im not sure i understand

Answer 3

(x^2+7x^2-2x-14)(x^3+x^2+2x+2)=0

(x^2+7x^2-2x-14)=0*(1/(x^3+x^2+2x+2))

(x^2+7x^2-2x-14)=0

Answer 4

oh ok so i got rid of one of those (.....) and now i can just find the zeros of this one i have left.

Answer 5

yup

Answer 6

and use that to do long div. and solve

Answer 7

understood. thanks

Answer 8

factor out or complete the square or quadratic formula

which ever you like.

Answer 9

or plug into calculator?

Answer 10

if your calc has solve for function

Answer 11

http://www.numberempire.com/equationsolver.php

Answer 12

i was just gonna plug it in. graph find the zeros. and use that as the divisor. for long div

Answer 13

you can graph and finds zeros :) yes

but you could have done that from the beginning withouth having to have divided by both sides :P

Answer 14

so when im given two things in parentheses = to zero.. i need to graph both of them or just one

Answer 15

It is a good idea to do both :)

Answer 16

First one then the other

Answer 17

ahh. ok i see, thanks

Answer 18

so to solve it can i do