Question

Find the equestion of the line that passes through the point (4,-1) and (5,-3)

Answer 1

slope = (-3-(-1))/(5-4)=-2
y=-2x+a
-3=-10+a a=7
y=-2x+7

Answer 2

slope = sub of y / sub of x
then plug in the point in y=mx+a

Answer 3

sorry how do you plug in the y=mx+a? thats not the answer? sorry I feel stupid I am just confuzed

Answer 4

What form you write the equation in matters.

Is it "slope intercept" form?

Answer 5

Slope = (y2 - y1)/(x2 - x1) = (-3+1)(5-4) = -2

y = -2x + b

Now, passing through 4, -1, you have b = -1 + 2(4) = 7

So, the equation is:
y = -2x + 7

Answer 6

You can also re-write it as:
2x + y = 7