what's the slope of Line perpendicular to line across(3,0)and(0,1),starting from (0,0)?!
Slope of a perpendicular line is its NEGATIVE RECIPROCAL.
First, determine the slope of the line, then its negative reciprocal.
y=mx+k y=-1/m+d !!
\(\Large \color{MidnightBlue}{\Rightarrow Slope = {y_{2} - y_{1} \over x_{2} - x_{1}} }\)
See my tutorial for more http://openstudy.com/study#/updates/4fb9f5a9e4b05565342ee28c
I get firest slope is -1/3 means the perpendicular is 3!!,?
I'm confused about the last part "starting from (0,0)?!" why do you need this if the information before it is all you need to find the slope
Of course.
You just need two pairs of co-ordinates. We have 3 here!
Or wait, the perpendicular line will start from 0,0?
ohhh yep I forget that easy now thanks
:P ok
but why from the draw I found the slope 2 but by your way you'll get 3 !!!! confused her ! or that not working with this kind of lines !!
|dw:1337938018460:dw| !!!
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