Question

Hillary is using the figure shown below to prove Pythagorean Theorem using triangle similarity.

In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.

the figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC.

Which of these could be a step to prove that BC2= AB2 + AC2?
Answer

Segment BD : segment BA = segment BA : segment CA, since triangle ADB is similar to triangle CDA.

Segment AD : segment CD = segment BD : segment AD, since triangle ADB is similar to triangle CDA.

Segment AC : segment DA = segme

Answer 1

ent BC : segment AC, since triangle ABC is similar to triangle DAC.

Segment BC : segment AC = segment AC : segment DC, since triangle ABC is similar to triangle DAC.

Answer 2

ok got it, but i cant be bothered to read your statements so you can match mine up :P

BD/AB = AB/BC (sim tri) [1]
hence
AB^2 = BC*BD

CD/AC = AC/BC (sim tri) [2]

AC^2 = BC*CD

hence

AC^2 + AB^2 = BC*CD + BC*BD = BC(BD + DC) = BC^2

AC^2 + AB^2 = BC^2
QED

Answer 3

thanks

Answer 4

so which choice is it??

Answer 5

@binary3i please tell me which answer this guy is referring too. i cant understand him.. i will give u best answer.. please

Answer 6

its not from the choice.
but he has do it correct.

Answer 7

so .. which one shud i pick?