how do i post a square root symbol in my question?
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OpenStudy (anonymous):
sqrt -
number
jimthompson5910 (jim_thompson5910):
type "sqrt(3)" to mean \[\Large \sqrt{3}\]
OpenStudy (anonymous):
sqrt - 49a^2
jimthompson5910 (jim_thompson5910):
so \[\Large \sqrt{49a^2}\] ??
OpenStudy (anonymous):
sqrt(49a^2)
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OpenStudy (anonymous):
yea
jimthompson5910 (jim_thompson5910):
You can write 49 as 7^2. So 49a^2 = 7^2a^2 = (7a)^2
This means 49a^2 = (7a)^2
Do you see what to do next?
OpenStudy (anonymous):
no im still learning these can u help?
OpenStudy (anonymous):
sqrt(x)
jimthompson5910 (jim_thompson5910):
The square root will undo the square. So effectively the two cancel out.
This means that the square root of (7a)^2 is 7a
So \[\Large \sqrt{(7a)^2} = 7a\]
So \[\Large \sqrt{49a^2} = 7a\]
This is assuming that 'a' is nonnegative.
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OpenStudy (anonymous):
my bad i typed it wrong its 49a^4
jimthompson5910 (jim_thompson5910):
Then 49a^4 = (7a^2)^2
So \[\Large \sqrt{(7a^2)^2} = 7a^2\]
and \[\Large \sqrt{49a^4} = 7a^2\]
OpenStudy (anonymous):
k thanks :)
jimthompson5910 (jim_thompson5910):
yw
OpenStudy (anonymous):
i got like 2-3 more questions would u mind helping?
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