Question

Ok, I'm lost here! Here are the questions:
A drawer contains 4 red socks, 3 white socks, and 3 blue socks. Without looking, you select a sock at random, replace it, and select a second sock at random. What is the probability that the first sock is blue and the second sock is red?

A lunch menu consists of 5 different sandwiches, 2 different soups, and 5 different drinks. How many choices are there for ordering a sandwich, a bowl of soup, and a drink?

The Burger Diner offers burgers with or without any or all of the following: catsup, lettuce, and mayonnaise. How many different burgers can you order?

Math is NOT my strong suit but I would loovvee it if you could explain how to do it! Thank ya!

Answer 1

sorry I accidentally pressed enter haha!

Answer 2

Probability of blue socks is 3/10 (3 blue socks out of 10 socks)
Probability of red socks is 4/10 (4 red socks out of 10 socks)
the question says and therefor the probabilities will be multipled
3/10*4/10
12/100=.12 or 3/25


Because there is selection, we will use combination
For ordering a sandwich 5 options are there and you need one so.. 5C1=5
For ordering a soup 2 options are there and you need one so.. 2C1=2
For ordering a drink 5 options are there and you need one so.. 5C1=5
You will multiply all these.
5C1*2C1*5C1=50


This is also about Combination,
You can skip all of them 4C0=1
You can have one of them 4C1=4
You can have two of them 4C2=6
You can have three of them 4C3=4
You can have all of them 4C4=1
Multiply all these
1*4*6*4*1=96

Answer 3

Wow thanks!!! I got it!! :D

Answer 4

no problem