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Given the domain values { -2, 0, 2 }, find the range values for the function y = 3x + 2.
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3(-2)+2 = -4 3(0)+2= 2 3(2)+2 = 8 Range: \( (-4,2,8) \)
I got the opposite of that 8,2-4 :/
could you answer another question for me please?
That's the same thing, order doesn't matter in sets.
In more general notation the answer is \( \{ -4,2,8 \} \)
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Put the equation in slope-intercept form and identify the slope of the line. 3x + 9y = 12 (Nobody else answered this when i had it posted)
I dont quite know how to work this out
\(3x + 9y = 12\) This is a equation of straight line. \( 3x + 9y = 12 \implies y = -\frac 13x+\frac 4 3 \) This is slope intercept form, where slope is \(-\frac 13\)
Ah. alright thanks @FoolForMath
Glad to help :)
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