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(x+3)^2
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x^2 + 6x +9
distribute the "^2" to get x^2+3^2
you would square the x and 3
nope.. I heard thats the wrong way. first way is right.
x^2+9 is not x^2+6x+9
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ur indeed correct Steeben because square x and then plus 2 times x times 3 and plus 3^2
\[(x+3)(x+3)\] Use FOIL
where are you getting 2x? (@JayDS )
it's not 2x but 6x since u times 2 by x by 3
Ok, I was thinking of a different way of solving a different kind of problem. Carry on.
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haha you guys are funny. you guys are all great kk thanks everyone :D
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