Differentiate w.r.t. x,

\large y=\ln \frac{ \sqrt[3]{2x^3-14}}{(1-x^2)^5}

Question

Differentiate w.r.t. x, 

\large y=\ln \frac{ \sqrt[3]{2x^3-14}}{(1-x^2)^5}

anonymous · Answer

\large y=\ln \frac{ \sqrt[3]{2x^3-14}}{(1-x^2)^5}$$y=In \sqrt[3]{2x^3-14}/(1-x^2)^5 $$

anonymous · Answer

$$y ' =x^2/x^3-7       - 10x/1-x^2 $$

experimentx · Answer

??

anonymous · Answer

My question is, should we differentiate it more?

experimentx · Answer

could you revise that question??

mimi_x3 · Answer

$$\large y = \frac{\ln\sqrt[3]{2x^{3}-14}}{(1-x^{2})^{5}}  $$
it didnt seem like youd differentiated it yet from what you post after it

anonymous · Answer

yes, I differentiated it. But I have to ask should I differentiate it more? or is that the answer?

experimentx · Answer

if you need to verify it ...you can wolfram it

anonymous · Answer

how can I write in wolfram this question? Can you please tell me

experimentx · Answer

use ()

mimi_x3 · Answer

experimentx · Answer

(ln(2x^^3 - 14)^(1/3))/(1-x^3)^5

anonymous · Answer

Thank you both of you for your time and help. :)