Question

if xy=28 yz=18 zx=14 and x , y , z>0 the value of x+ y + z is equal to?

Answer 1

@experimentX @glgan1

Answer 2

must be some error there xy=28 yx=18

Answer 3

sorry yz=18

Answer 4

\[y=\frac {28}x\]\[z=\frac{14}x\]so\[yz=(\frac{28}x)(\frac{14}x)=18\]should work...

Answer 5

wat u r trying to say plzz help me dude.......................

Answer 6

I'm sort of thinking out loud...

Answer 7

\[yz=\frac{392}{x^2}=18\implies x=\frac{14}3\]now you can get the other numbers

Answer 8

\[
x=\frac{28}{y}\\
z=\frac{18}{y}\\
14=\frac{28} y \frac{y}{18}

y=6

\]

Answer 9

When a student ask for help and you try to help, they issue you a warning unless you
say some jargon between each step.
@open_study1 sent me a pm to help.