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Mathematics
OpenStudy (anonymous):

Find the number of sides of a regular polygon if one interior angle is 120 degrees. 3 4 5 6

OpenStudy (anonymous):

Do you know what a regular polygon is?

OpenStudy (anonymous):

If I think it is what it is, then two of the angles have to be 120 right? So 120x2 = 240, that leaves 120

OpenStudy (anonymous):

that means 3 sides do you follow my logic (i hope you are actually learning and not using this to finish last minute hw)

OpenStudy (anonymous):

A polygon with all the angles equal and all the sides equal.

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

ok so im kind of under stand n what you are say n

OpenStudy (anonymous):

Can you plz explain more

OpenStudy (anonymous):

yup, so 360/120 = 3, 360 degrees and you must have 120 angles so divide 360 by 120 and you get how many times you can have 120 degree angle given a 360 degree constraint

OpenStudy (anonymous):

i will draw to help

OpenStudy (anonymous):

ur so much HELP @seldamat

OpenStudy (anonymous):

Thanks for the help

OpenStudy (anonymous):

crappy drawing - but you know that you have one angle that is 120, and that all angles must add up to 360. (i drew it wrong)

OpenStudy (anonymous):

You also know that all the angles are equal, so you can divide 360, by 120 to know how many times you can have 120 degree angles given a max of 360 total degrees

OpenStudy (anonymous):

hey can you help with my next ?

OpenStudy (anonymous):

im just hanging out till someone helps me with my prob :\

OpenStudy (anonymous):

i can try

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