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Physics
OpenStudy (anas.p):

Ok pls help me.. i have a problem with question c. I know the answer, the method is a problem. Question below.

OpenStudy (anas.p):

OpenStudy (vincent-lyon.fr):

This file extension does not open in any computer. Image is better.

OpenStudy (anas.p):

here take a direct link to the website.... http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w07_qp_2.pdf question 4 part c

OpenStudy (anas.p):

btw thats word pad file....

OpenStudy (jamesj):

Which question?

OpenStudy (vincent-lyon.fr):

You have to work out minimum area to coincide with maximum stress (where it breaks) and applied force.

OpenStudy (anas.p):

yes i got that... i got the minimum cos section area but the question asks maximum area..

OpenStudy (anas.p):

@JamesJ question 4 c

OpenStudy (jamesj):

What VL means is figure out the minimum cross-sectional area of the rod (i.e., x-sectional area of the rod less the x-sectional area of the bubble) such that the rod doesn't break. And then that gives you the maximum area of the bubble is, and from that you can deduce its volume.

OpenStudy (anas.p):

Stress =Force/Area stress is 9.5*10^8 force is 1.9*10^3 Area = Force/Stress Area = (1.9*10^3)/( 9.5*10^8) Area =2*10^6 Then what do I do?

OpenStudy (vincent-lyon.fr):

You mean Area of matter = \(2\: 10^{\color {red}-6}\) Then subtract this area from total cross section of the bar.

OpenStudy (anas.p):

Why do I do that? How does that give me the Maximum cross sectional area.( I know u r right but i am not able to understand?)

OpenStudy (vincent-lyon.fr):

Maximum cross section of hole = Total cross section - Minimum cross section of actual matter.

OpenStudy (anas.p):

Cool Thanks man....

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