Ok pls help me.. i have a problem with question c. I know the answer, the method is a problem. Question below.

6 years agoThis file extension does not open in any computer. Image is better.

6 years agohere take a direct link to the website.... http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w07_qp_2.pdf question 4 part c

6 years agobtw thats word pad file....

6 years agoWhich question?

6 years agoYou have to work out minimum area to coincide with maximum stress (where it breaks) and applied force.

6 years agoyes i got that... i got the minimum cos section area but the question asks maximum area..

6 years ago@JamesJ question 4 c

6 years agoWhat VL means is figure out the minimum cross-sectional area of the rod (i.e., x-sectional area of the rod less the x-sectional area of the bubble) such that the rod doesn't break. And then that gives you the maximum area of the bubble is, and from that you can deduce its volume.

6 years agoStress =Force/Area stress is 9.5*10^8 force is 1.9*10^3 Area = Force/Stress Area = (1.9*10^3)/( 9.5*10^8) Area =2*10^6 Then what do I do?

6 years agoYou mean Area of matter = \(2\: 10^{\color {red}-6}\) Then subtract this area from total cross section of the bar.

6 years agoWhy do I do that? How does that give me the Maximum cross sectional area.( I know u r right but i am not able to understand?)

6 years agoMaximum cross section of hole = Total cross section - Minimum cross section of actual matter.

6 years agoCool Thanks man....

6 years ago