OpenStudy (anas.p):

Ok pls help me.. i have a problem with question c. I know the answer, the method is a problem. Question below.

6 years ago
OpenStudy (anas.p):

6 years ago
OpenStudy (vincent-lyon.fr):

This file extension does not open in any computer. Image is better.

6 years ago
OpenStudy (anas.p):

here take a direct link to the website.... http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w07_qp_2.pdf question 4 part c

6 years ago
OpenStudy (anas.p):

6 years ago
OpenStudy (jamesj):

Which question?

6 years ago
OpenStudy (vincent-lyon.fr):

You have to work out minimum area to coincide with maximum stress (where it breaks) and applied force.

6 years ago
OpenStudy (anas.p):

yes i got that... i got the minimum cos section area but the question asks maximum area..

6 years ago
OpenStudy (anas.p):

@JamesJ question 4 c

6 years ago
OpenStudy (jamesj):

What VL means is figure out the minimum cross-sectional area of the rod (i.e., x-sectional area of the rod less the x-sectional area of the bubble) such that the rod doesn't break. And then that gives you the maximum area of the bubble is, and from that you can deduce its volume.

6 years ago
OpenStudy (anas.p):

Stress =Force/Area stress is 9.5*10^8 force is 1.9*10^3 Area = Force/Stress Area = (1.9*10^3)/( 9.5*10^8) Area =2*10^6 Then what do I do?

6 years ago
OpenStudy (vincent-lyon.fr):

You mean Area of matter = $$2\: 10^{\color {red}-6}$$ Then subtract this area from total cross section of the bar.

6 years ago
OpenStudy (anas.p):

Why do I do that? How does that give me the Maximum cross sectional area.( I know u r right but i am not able to understand?)

6 years ago
OpenStudy (vincent-lyon.fr):

Maximum cross section of hole = Total cross section - Minimum cross section of actual matter.

6 years ago
OpenStudy (anas.p):

Cool Thanks man....

6 years ago