Question

Ok pls help me.. i have a problem with question c.
I know the answer, the method is a problem.
Question below.

Answer 1

This file extension does not open in any computer. Image is better.

Answer 2

here take a direct link to the website....
http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w07_qp_2.pdf
question 4 part c

Answer 3

btw thats word pad file....

Answer 4

Which question?

Answer 5

You have to work out minimum area to coincide with maximum stress (where it breaks) and applied force.

Answer 6

yes i got that... i got the minimum cos section area but the question asks maximum area..

Answer 7

@JamesJ question 4 c

Answer 8

What VL means is figure out the minimum cross-sectional area of the rod (i.e., x-sectional area of the rod less the x-sectional area of the bubble) such that the rod doesn't break. And then that gives you the maximum area of the bubble is, and from that you can deduce its volume.

Answer 9

Stress =Force/Area
stress is 9.5*10^8
force is 1.9*10^3
Area = Force/Stress
Area = (1.9*10^3)/( 9.5*10^8)
Area =2*10^6

Then what do I do?

Answer 10

You mean Area of matter = \(2\: 10^{\color {red}-6}\)

Then subtract this area from total cross section of the bar.

Answer 11

Why do I do that? How does that give me the Maximum cross sectional area.( I know u r right but i am not able to understand?)

Answer 12

Maximum cross section of hole = Total cross section - Minimum cross section of actual matter.

Answer 13

Cool Thanks man....

Answer 14

covalent compound CCl4?

Answer 15

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Express your answer as a chemical formula.

Answer 16

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Answer 17

need calc checked and finished

Answer 18

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Answer 19

IS this right?

Answer 20

A 10" diameter pumpkin pie is cut into six equal servings.
What is the approximate area of the top of each piece of pie?

3.

Answer 21

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Answer 22

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Answer 23

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Answer 24

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Answer 25

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I give up on cooking my own food.

Answer 26

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25x^2 u2212 110x + 121
25x^2 u22

Answer 27

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Answer 28

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Answer 29

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Answer 30

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Answer 31

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Answer 32

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Answer 33

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2x2y2 + 3x4y + 10x6
4x4