OpenStudy (anonymous):

A force of 55 pounds is exerted along a rope attached to a crate at an angle of 30o above the horizontal. The crate is moved 32 feet. How much work has been accomplished? Round answer to one decimal place.

6 years ago
jimthompson5910 (jim_thompson5910):

Use the idea that Work = Force * Displacement

6 years ago
OpenStudy (savvy):

more accurately...WORK = FORCE.DISPLACEMENT it's the dot product of force vector and displacement vector...

6 years ago
OpenStudy (anonymous):

how do i figure out which numbers go where in the formula?

6 years ago
jimthompson5910 (jim_thompson5910):

The given force is 55 pounds and the displacement is 32 feet (since the object is moved 32 feet)

6 years ago
OpenStudy (savvy):

ok....you know about the DOT PRODUCT...???

6 years ago
OpenStudy (anonymous):

@Savvy yes i know about the dot product... there is no need to make me feel bad for not knowing how to solve a problem

6 years ago
OpenStudy (savvy):

OMG...am soooo sorry i didn't mean that...

6 years ago
OpenStudy (anonymous):

So the answer is just 1760 then? I figured it would be more complicated than that...

6 years ago
jimthompson5910 (jim_thompson5910):

I think in this case, all you're doing is just multiplying the two numbers since I think that the force of 55 pounds is the force along the rope (and not the horizontal force)

6 years ago
jimthompson5910 (jim_thompson5910):

if it is the horizontal force, then you'll be multiplying 55 by 32*cos(30), but I don't think that's the case here.

6 years ago
OpenStudy (anonymous):

@Savvy maybe something got lost in translation on the internet. it's fine.

6 years ago
OpenStudy (savvy):

|dw:1338065379060:dw| you can take the dot product....

6 years ago