Find the specified nth term in the expansion of the binomial. (Write the expansion in descending powers of x.) (x - 4y)6, n = 3

so you want the 3rd term ? of (x - 4y)^6

x^6-24*x^5*y+240*x^4*y^2-1280*x^3*y^3+3840*x^2*y^4-6144*x*y^5+4096*y^6 wouldn't it be -1280*x^3*y^3 ?

Yeah. Possible answers are: A. 20x3y3 B. 240x4y2 C. 20x3y3 D. 4096y6 E. 120x3y3

basically do this (x - 4y)(x - 4y)(x - 4y)(x - 4y)(x - 4y)(x - 4y)

240*x^4*y^2

oops I didn't see that x^6 first time lol

x^6-24*x^5*y+240*x^4*y^2-1280*x^3*y^3+3840*x^2*y^4 1 2 (3) 4 5... -6144*x*y^5+4096*y^6

So, how does that end up being one of the possible answers?

basically do this (x - 4y)(x - 4y)(x - 4y)(x - 4y)(x - 4y)(x - 4y) use binomial theorem or distribute it all out. sort it in descending x order as your question states. and just find the 3rd term.

What about the 6?

(x - 4y)6 ^ this 6 that means multiply (x-4y) by itself 6 times and you actually wrote it wrong it is (x - 4y)^6 the ^ means to the power of ...

Sorry, my smaller raised number must have copied differently. I know it's ^

no need for sorries :)

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