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how can we get electric field from electric potential?
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\[V=E.d\]
too*there is one eq of maxwell too but i dont remember
\[Vab=Va-Vb=\int\limits_{a}^{?b}Edl\]
from that formula
your E is a constant in thah line?
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yep
take it off \[E.\int\limits_{a}^{2.b}dl=E(2.b-a)\]
where is electic potential?
you said Vab=E(2.b-a)
oh i get it thanks.
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A point charge Q is located at the center of a cube of side L. In addition, six other identical point charges q inside the cube are positioned symmetrically around Q, as shown in Fig. 4. Determine the electric flux through one face of the cube.
could you put the pic?
that is the picture
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