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use the shell method to find the volume of the solid below the surface of revolution and above the xy-plane. The curve z=3sin(y), (o<=y<=pi), in the yz plane is revolved about the z-axis
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it is number 3 on the attached file
is that 3sin(theta)?
i mean 3 sin (y)
I get this -(9/2)*Pi*(cos(Pi)*sin(Pi)-Pi)
intigrate pi*(3*sin(y))^2 from 0 to pi with respect to y
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44.4132198
thank you!!!
is it right?
actually its 6pi squared
grr it is of by 14
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