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Mathematics
Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight. 29 and 31 39 and 41 49 and 51
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If x is the odd number, then x + 2 will be the next one. Then if you read it carefully, you'll get this. \(\Large \color{MidnightBlue}{\Rightarrow {3 \over 7}x + {1 \over 3}(x + 2) = 38 }\) SOLVE.
it would be the secomnd answer
Ummm nope
then the first?
Why don't you try it?
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ok
ya im not sure how
obvio, it's the third one.
Plug in the values.
how
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see, the first part says three-sevenths, and the number at the end is a whole number, so obviously the first number has to be divisible by 7, and the only option is 49.
oh ok thank you
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