Question

Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight.
29 and 31
39 and 41
49 and 51

Answer 1

If x is the odd number, then x + 2 will be the next one.
Then if you read it carefully, you'll get this.

\(\Large \color{MidnightBlue}{\Rightarrow {3 \over 7}x + {1 \over 3}(x + 2) = 38 }\)

SOLVE.

Answer 2

it would be the secomnd answer

Answer 3

Ummm nope

Answer 4

then the first?

Answer 5

Why don't you try it?

Answer 6

ok

Answer 7

ya im not sure how

Answer 8

obvio, it's the third one.

Answer 9

Plug in the values.

Answer 10

how

Answer 11

see, the first part says three-sevenths, and the number at the end is a whole number, so obviously the first number has to be divisible by 7, and the only option is 49.

Answer 12

oh ok thank you

Answer 13

http://www.google.co.in/search?sugexp=chrome,mod=19&sourceid=chrome&ie=UTF-8&q=3%2F7+*+49+%2B+1%2F3+*+51