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OpenStudy (anonymous):

Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is equal to thirty-eight. 29 and 31 39 and 41 49 and 51

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Parth (parthkohli):

If x is the odd number, then x + 2 will be the next one. Then if you read it carefully, you'll get this. \(\Large \color{MidnightBlue}{\Rightarrow {3 \over 7}x + {1 \over 3}(x + 2) = 38 }\) SOLVE.

OpenStudy (anonymous):

it would be the secomnd answer

Parth (parthkohli):

Ummm nope

OpenStudy (anonymous):

then the first?

Parth (parthkohli):

Why don't you try it?

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OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ya im not sure how

OpenStudy (anonymous):

obvio, it's the third one.

Parth (parthkohli):

Plug in the values.

OpenStudy (anonymous):

how

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OpenStudy (anonymous):

see, the first part says three-sevenths, and the number at the end is a whole number, so obviously the first number has to be divisible by 7, and the only option is 49.

OpenStudy (anonymous):

oh ok thank you

Parth (parthkohli):

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