Geometry problem #2 *Old rule: no calculator!*
Area of the polygon-12 * area of the 1 cm side equilateral triangle. Am I missing something?
I think that's it :)
You could find the area of the entire polygon by breaking it into triangles and multiplying the area of that triangle by 12: |dw:1338109350047:dw| If you divide that triangle in half, it becomes a right triangle so you can use the magic of trigonometric functions to find the height. |dw:1338109449920:dw| Once you have the height, you can just find the area of the triangle using "A=1/2 bh", and then multiply by 12 to get area of the regular 12-sided polygon.
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