Ask
your own question, for FREE!
Mathematics
8 Online
Differentiate using product rule:
Still Need Help?
Join the QuestionCove community and study together with friends!
Here is the question: \[h(x)=(x^2+5x+7).(x^3+2x-4)\]
right? \[(2x+5)(3x^2+2) \]
let \[u = x^2 + 5x + 7 ===> \frac{du}{dx} = 2x + 5\] \[v = x^3 + 3x - 4 ===> \frac{dv}{dx} = 3x^2 + 3\] then \[\frac{dy}{dx} = u \times \frac{dv}{dx} + v \times \frac{ du}{dx}\]
just substitute and simplify
(f(x).g(x))' = f(x).g'(x) + g(x).f'(x)
Still Need Help?
Join the QuestionCove community and study together with friends!
yes let me do it. \[(x^2+5x+7) (3x^2+2) + (2x+5)(x^3+2x-4)\]
is that right?
yup. looks right to me
Now, I am confuse with the next part. I cannot simplify. :(
normally you would be expected to simplify.... not sure on your question requirements
Still Need Help?
Join the QuestionCove community and study together with friends!
yes I have to simplify it after applying product rule.
a simple method is to draw up a grid |dw:1338113768920:dw|
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Countless7Echos:
I don't know just no sketch doodle day :p finished a video already so I'm pretty
Ferrari:
Depression Hi, it's me, Jordan (ferrari). It's supposed to be the Fourth of July but I feel kinda depressed and mad at myself for no reason.
Countless7Echos:
mmm I forgot to post but hey first time trying out hyperpop art :3 super fun TW:
RAVEN69:
The hole You can't fix the hole in my heart. It's permanent. It's been broken to many times and I love it every time.
5 hours ago
9 Replies
2 Medals
6 hours ago
12 Replies
1 Medal
1 day ago
9 Replies
5 Medals
2 days ago
0 Replies
0 Medals