Ask your own question, for FREE!
Physics
OpenStudy (anonymous):

What is the energy of the photons with wavelengths as follows: a) 450 nm b) 45.0 nm c) 4:50 nm

OpenStudy (stormfire1):

The formula to find the energy of a photon given its wavelength is:\[E = \frac{hc}{\lambda}\]where h = planck's constant, c is the speed of light and lambda is the wavelength. I'll do the first one for you as an example:\[E=\frac{(6.626x10^{-34}m^2 kg/s)(3x10^8 m/s)}{4.5x10^{-7}m}=4.4x10^{-19}J\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!