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OpenStudy (anonymous):

What is the energy of the photons with wavelengths as follows: a) 450 nm b) 45.0 nm c) 4:50 nm

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OpenStudy (stormfire1):

The formula to find the energy of a photon given its wavelength is:\[E = \frac{hc}{\lambda}\]where h = planck's constant, c is the speed of light and lambda is the wavelength. I'll do the first one for you as an example:\[E=\frac{(6.626x10^{-34}m^2 kg/s)(3x10^8 m/s)}{4.5x10^{-7}m}=4.4x10^{-19}J\]

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