Ask your own question, for FREE!
Mathematics
OpenStudy (anonymous):

Please,help! Can someone explain how this equation (2(-L√S Cos[L√S]+Sin[L√S]))/LS; S=(2k+1)*Pi ⁄ 2*L)^2;k=0,1,2.. can be equal to 2(-1)^k/LS

OpenStudy (anonymous):

im sorry,mistake S=( (2k+1)*Pi ⁄ 2*L )^2

OpenStudy (experimentx):

?? can you write it in equation??

OpenStudy (anonymous):

(2(-L*((2k+1)*pi/2L) Cos[(2k+1)*pi/2]+Sin[(2k+1)*pi/2]))/( L [(2k+1)*pi/2*L]^2 Did you mean like this ?

OpenStudy (experimentx):

http://www.codecogs.com/latex/eqneditor.php

OpenStudy (anonymous):

I solved it.

OpenStudy (experimentx):

congrats ...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!