Question

cot y, if csc y=-10/3 and cos y<0
Evaluate w/o using a calculator. No decimal answers and use pi radians if necessary.

Answer 1

help!!

Answer 2

help!

Answer 3

y=((180 (2 π ℕ_3 +((π arcsin(((3)/(10))))/(180))+π))/(π))

Answer 4

I don't understand that equation

Answer 5

u searching for y , ?

Answer 6

\[\csc(y)=-\frac{10}{3}\implies \sin(x)=-\frac{3}{10}\]

Answer 7

we get by pythagoras third side is
\[\sqrt{10^2-3^2}=\sqrt{100-9}=\sqrt{91}\] so
\[\cos(y)=-\frac{\sqrt{91}}{10}\]

Answer 8

well the y is more like this

Answer 9

\[\cot(y)=\frac{\sqrt{91}}{3}\]

Answer 10

doesn't matter what the y looks like. you want
\[\cot(y)\] or
\[\cot(\zeta)\] or whatever

Answer 11

\[\cot(\gamma)\]i bet

Answer 12

\[\cot \gamma\]

Answer 13

yes!

Answer 14

@jeessicaaahh name of variable is not an issue here. you are not looking for \(\gamma\) (it is the greek letter gamma) but you are looking for \(\cot(\gamma)\)

Answer 15

yes, yes i am.

Answer 16

you need to find all three sides of the right triangle, and then you can find it by looking

Answer 17

by looking .. ?

Answer 18

do i use the drawing you gave me to help?

Answer 19

yes find the third side

Answer 20

cosecant you can think of as "hypotenuse over opposite" so label the triangle that way, and then find the third side

Answer 21

close
\[\cos(\gamma)=-\frac{\sqrt{91}}{10}\] you know it is negative because you are told

Answer 22

i mean you are told that it is negative

Answer 23

yes, so my answer is 3 ?

Answer 24

cotangent is adjacent over opposite, and that is what you are looking for

Answer 25

adjacent is \(\sqrt{91}\) and opposite is 3

Answer 26

got it?

Answer 27

i got 3 is that correct ?

Answer 28

no it is not 3, it is the ratio \(\frac{\sqrt{91}}{3}\)

Answer 29

adjacent over opposite