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OpenStudy (anonymous):

cot y, if csc y=-10/3 and cos y<0 Evaluate w/o using a calculator. No decimal answers and use pi radians if necessary.

OpenStudy (anonymous):

help!!

OpenStudy (anonymous):

help!

OpenStudy (anonymous):

y=((180 (2 π ℕ_3 +((π arcsin(((3)/(10))))/(180))+π))/(π))

OpenStudy (anonymous):

I don't understand that equation

OpenStudy (anonymous):

u searching for y , ?

OpenStudy (anonymous):

\[\csc(y)=-\frac{10}{3}\implies \sin(x)=-\frac{3}{10}\]

OpenStudy (anonymous):

|dw:1338142771984:dw|

OpenStudy (anonymous):

we get by pythagoras third side is \[\sqrt{10^2-3^2}=\sqrt{100-9}=\sqrt{91}\] so \[\cos(y)=-\frac{\sqrt{91}}{10}\]

OpenStudy (anonymous):

|dw:1338142851721:dw| well the y is more like this

OpenStudy (anonymous):

\[\cot(y)=\frac{\sqrt{91}}{3}\]

OpenStudy (anonymous):

doesn't matter what the y looks like. you want \[\cot(y)\] or \[\cot(\zeta)\] or whatever

OpenStudy (anonymous):

\[\cot(\gamma)\]i bet

OpenStudy (anonymous):

\[\cot \gamma\]

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

@jeessicaaahh name of variable is not an issue here. you are not looking for \(\gamma\) (it is the greek letter gamma) but you are looking for \(\cot(\gamma)\)

OpenStudy (anonymous):

yes, yes i am.

OpenStudy (anonymous):

you need to find all three sides of the right triangle, and then you can find it by looking

OpenStudy (anonymous):

by looking .. ?

OpenStudy (anonymous):

do i use the drawing you gave me to help?

OpenStudy (anonymous):

yes find the third side

OpenStudy (anonymous):

cosecant you can think of as "hypotenuse over opposite" so label the triangle that way, and then find the third side

OpenStudy (anonymous):

close \[\cos(\gamma)=-\frac{\sqrt{91}}{10}\] you know it is negative because you are told

OpenStudy (anonymous):

i mean you are told that it is negative

OpenStudy (anonymous):

yes, so my answer is 3 ?

OpenStudy (anonymous):

cotangent is adjacent over opposite, and that is what you are looking for

OpenStudy (anonymous):

adjacent is \(\sqrt{91}\) and opposite is 3

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

i got 3 is that correct ?

OpenStudy (anonymous):

no it is not 3, it is the ratio \(\frac{\sqrt{91}}{3}\)

OpenStudy (anonymous):

adjacent over opposite

OpenStudy (anonymous):

|dw:1338143722809:dw|

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