Mathematics
OpenStudy (anonymous):

cot y, if csc y=-10/3 and cos y<0 Evaluate w/o using a calculator. No decimal answers and use pi radians if necessary.

OpenStudy (anonymous):

help!!

OpenStudy (anonymous):

help!

OpenStudy (anonymous):

y=((180 (2 π ℕ_3 +((π arcsin(((3)/(10))))/(180))+π))/(π))

OpenStudy (anonymous):

I don't understand that equation

OpenStudy (anonymous):

u searching for y , ?

OpenStudy (anonymous):

$\csc(y)=-\frac{10}{3}\implies \sin(x)=-\frac{3}{10}$

OpenStudy (anonymous):

|dw:1338142771984:dw|

OpenStudy (anonymous):

we get by pythagoras third side is $\sqrt{10^2-3^2}=\sqrt{100-9}=\sqrt{91}$ so $\cos(y)=-\frac{\sqrt{91}}{10}$

OpenStudy (anonymous):

|dw:1338142851721:dw| well the y is more like this

OpenStudy (anonymous):

$\cot(y)=\frac{\sqrt{91}}{3}$

OpenStudy (anonymous):

doesn't matter what the y looks like. you want $\cot(y)$ or $\cot(\zeta)$ or whatever

OpenStudy (anonymous):

$\cot(\gamma)$i bet

OpenStudy (anonymous):

$\cot \gamma$

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

@jeessicaaahh name of variable is not an issue here. you are not looking for $$\gamma$$ (it is the greek letter gamma) but you are looking for $$\cot(\gamma)$$

OpenStudy (anonymous):

yes, yes i am.

OpenStudy (anonymous):

you need to find all three sides of the right triangle, and then you can find it by looking

OpenStudy (anonymous):

by looking .. ?

OpenStudy (anonymous):

do i use the drawing you gave me to help?

OpenStudy (anonymous):

yes find the third side

OpenStudy (anonymous):

cosecant you can think of as "hypotenuse over opposite" so label the triangle that way, and then find the third side

OpenStudy (anonymous):

close $\cos(\gamma)=-\frac{\sqrt{91}}{10}$ you know it is negative because you are told

OpenStudy (anonymous):

i mean you are told that it is negative

OpenStudy (anonymous):

yes, so my answer is 3 ?

OpenStudy (anonymous):

cotangent is adjacent over opposite, and that is what you are looking for

OpenStudy (anonymous):

adjacent is $$\sqrt{91}$$ and opposite is 3

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

i got 3 is that correct ?

OpenStudy (anonymous):

no it is not 3, it is the ratio $$\frac{\sqrt{91}}{3}$$

OpenStudy (anonymous):

OpenStudy (anonymous):

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