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Algebra Mixture: a chemist has 80 ml of a solution containing 20% acid. How many ml must he romove and replace with pure acid to obtain a 40% solution of acid?
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well. so i am assuming that is 20% V/V. so, 80 ml has 20% acid - what is the volume of acid in those 80 mls then?
the question doesn't include the volume
Do you know the right answer?
No :(
Let x = the amount of pure acid to be added .20(80-x)+1.00x=.40(80)
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Tysm you really helped me! I get it now :)
yw. What is the answer?
x=20
Good job!!
thnx xD
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|dw:1338160420201:dw| \[\frac 14 \times 80 = 20 L \]
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