Question

Algebra Mixture:
a chemist has 80 ml of a solution containing 20% acid. How many ml must he romove and replace with pure acid to obtain a 40% solution of acid?

Answer 1

well. so i am assuming that is 20% V/V.

so, 80 ml has 20% acid - what is the volume of acid in those 80 mls then?

Answer 2

the question doesn't include the volume

Answer 3

Do you know the right answer?

Answer 4

No :(

Answer 5

Let x = the amount of pure acid to be added
.20(80-x)+1.00x=.40(80)

Answer 6

Tysm you really helped me! I get it now :)

Answer 7

yw. What is the answer?

Answer 8

x=20

Answer 9

Good job!!

Answer 10

thnx xD

Answer 11

\[\frac 14 \times 80 = 20 L \]