Question

For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions.

Can someone please show me the steps of how to do this? Thanks! :)

Answer 1

I think that factoring is the best solution, and if you think about it, then we can put j as 2.

2 * 1 = 2
2 + 1 = 3

j = 2

Answer 2

Let's try to factor it further.

\(\Large \color{Black}{\Rightarrow x^2 + 2x + x + 2 }\)
\(\Large \color{Black}{\Rightarrow x(x + 2) + 1(x + 2) }\)
\(\Large \color{Black}{\Rightarrow (x + 1)(x + 2) }\)

x = -1 or -2(two solutions :D)

Answer 3

Thanks so much!