The sum of all odd numbers form 1 to 99 is?
use sum of aritmetic sequence. .
1 + 3 + 5 + 7.....But you need not do that since it is an arithmetic sequence.
The sum of an arithmetic sequence is: \(\Large \color{Black}{\Rightarrow {n \over 2}(a_1 + a_l) }\) a1 is the first term aL is the last n is the number of terms
After 1 add? Should i cross multiply?
1st term is 1. Last is 99. Odd numbers between 1,100 are 50.
The common difference is d, btw.
@ParthKohli , i think you've mistaken the formula. . http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithSeq.htm
Oops, it was aN lol
it's ok. .
I dont get it XD
Hey I know another pattern.
The sum of first n odd numbers is n squared. The sum of first 50 odd numbers is 50 squared. So, 50^2 = 2500
Well actually my formula was correct.
I learnt this pattern at school.
Ca you give me an example?
For example the sum of first 4 odd numbers is 4 squared aka 16 1 + 3 + 5 + 7 = 4 + 12 = 16
how did you got that formula? @ParthKohli
Oh wait a second
Yes....yes I'm correct.
the answer is 2500, and you're correct, but how did you get that another formula?
I learnt that at school
@sel126 Got it?
Yessss :) Thankyousomuch:)))))))
Yw :D
99 = a + (n-1)d hence 99 = 1 +(n-1)*3 n= 50 substituting value of n in equation S= n/2 [ 2a + (n-1)*d] we get sum of odd terms that is equal to 2500 where a =1(first term) and d =3(common difference)
Why does three become the d?
the sum of odd numbers is a perfect square
That's what I said above
Hehe don't waste your energy, genius. I've explained her.
just thought i would mention it. no need for a formula, or all that other business, only need to know how many numbers are being added
Hmm I said the exact same thing.
Still here you have a medal
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