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OpenStudy (anonymous):

In the sequence 16^2 + 4, 8x^2 + 3, 4x^2 + 2, 2x^2 + 1, what is the next term?

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Parth (parthkohli):

The co-efficient of x^2 is getting divided by 2 and the other term is decreasing by 1 every time. So the next one should be \(1x^2 + 0\) aka \(x^2\)

Parth (parthkohli):

Do you get it?

OpenStudy (anonymous):

1^2 +0

OpenStudy (anonymous):

Yeahhhhhhh. :)) Thanks!

Parth (parthkohli):

@open_study1 1x^2 + 0 actually

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OpenStudy (anonymous):

sorry i missed that x

Parth (parthkohli):

:) no worries

OpenStudy (anonymous):

ok)))));;

OpenStudy (anonymous):

1x^2+0

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