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Mathematics
In the sequence 16^2 + 4, 8x^2 + 3, 4x^2 + 2, 2x^2 + 1, what is the next term?
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The co-efficient of x^2 is getting divided by 2 and the other term is decreasing by 1 every time. So the next one should be \(1x^2 + 0\) aka \(x^2\)
Do you get it?
1^2 +0
Yeahhhhhhh. :)) Thanks!
@open_study1 1x^2 + 0 actually
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sorry i missed that x
:) no worries
ok)))));;
1x^2+0
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