Question

Please help with this question. Please show every step of the solution. MEDALS WILL BE APLENTY!!!

Answer 1

Lol we don't need medals :P

Answer 2

you do know you cant vouch medals will be aplenty

Answer 3

therefore shall we go away now?

Answer 4

Bye!

Answer 5

really soz ill post my question in a sec

Answer 6

here it is

Answer 7

thanks guys in advance

Answer 8

Find the cube of both sides =.=

Answer 9

ugh you couldnt have written that =_= :p lol anyway substitute x

Answer 10

that should be your first step

Answer 11

just take cube of both sides and factor 6 out lol

Answer 12

yeh i have done all that but i can't seem to get the answer

Answer 13

\(\Large \color{Black}{\Rightarrow (a + b)^3 = a^3 + b^3 + 3ab^2 + 3a^2b }\)

Answer 14

It's not equal to 4! If you multiply it will equal 4

Answer 15

Yes use the formula @ParthKohli gave you.

Answer 16

substute x is still the first step...something is wrong with my algebra today @_@ lol

Answer 17

@lgbasallote I can teach you algebra xD

Answer 18

oh ok guys yep i got it. i love this website !!!XDXD

Answer 19

Lol you should be loving the site

Answer 20

i just answered 10 algebra questions wrong o.O what is wrong with me =_= lol

Answer 21

\[\large (\sqrt[3]{2}+\sqrt[3]{4})^3=\sqrt[3]{2^3}+3*\sqrt[3]{2^2}*\sqrt[3]4+3*\sqrt[3]2*\sqrt[3]{4^2}+\sqrt[3]{4^3}\]\[\large=2+3*\sqrt[3]{16}+3*\sqrt[3]{16}+4\]\[\large=6+6*\sqrt[3]{16}=6(1+\sqrt[3]{16})\]That's the closest I can get.