If f(x)=√(x^3)-1, find the solution to the equation f(x)=f^-1(x).

Question

parthkohli · Answer

Let's say f(x) = y

$\Large \color{Black}{\Rightarrow y= \sqrt{x - 3} - 1 }$

$\Large \color{Black}{\Rightarrow y  +1 = \sqrt{x - 3} }$

$\Large \color{Black}{\Rightarrow y^2 + 2y + 1 = x - 3 }$

$\Large \color{Black}{\Rightarrow x = y^2 + 2y  +4 }$

So, it will be f(x) right? So it's just $x^2 + 2x + 4$

anonymous · Answer

my question says x cubed under a square root.

anonymous · Answer

@ParthKohli

parthkohli · Answer

Oh no

parthkohli · Answer

Can you do it still? I've given a big hint

anonymous · Answer

i dont know what to do after y+1=sqrt of x^3

parthkohli · Answer

I'm sleepy *yawns*

anonymous · Answer

why are you on a math study group then?

parthkohli · Answer

I'm here to help you, not to give the answers.

anonymous · Answer

not doing a very good job helping

anonymous · Answer

Is the following true:$$f(x)=\sqrt{x^3}-1 $$