Question

If f(x)=√(x^3)-1, find the solution to the equation f(x)=f^-1(x).

Answer 1

Let's say f(x) = y

\(\Large \color{Black}{\Rightarrow y= \sqrt{x - 3} - 1 }\)

\(\Large \color{Black}{\Rightarrow y +1 = \sqrt{x - 3} }\)

\(\Large \color{Black}{\Rightarrow y^2 + 2y + 1 = x - 3 }\)

\(\Large \color{Black}{\Rightarrow x = y^2 + 2y +4 }\)

So, it will be f(x) right? So it's just \(x^2 + 2x + 4\)

Answer 2

my question says x cubed under a square root.

Answer 3

@ParthKohli

Answer 4

Oh no

Answer 5

Can you do it still? I've given a big hint

Answer 6

i dont know what to do after y+1=sqrt of x^3

Answer 7

I'm sleepy *yawns*

Answer 8

why are you on a math study group then?

Answer 9

I'm here to help you, not to give the answers.

Answer 10

not doing a very good job helping

Answer 11

Is the following true:\[f(x)=\sqrt{x^3}-1 \]