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What is the solution to the equation 9^(x + 1) = 27 ? x = 2.5 x = 0.5 x = -0.5 x = -3.5 stuck on this!
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9^(x + 1) = 27 (3^2)^(x + 1) = 3^3 3^(2(x+1)) = 3^3 Since the bases are equal, the exponents are equal. So 2(x+1) = 3 I'll let you continue
i guess it's D
no.. you need to solve for x in jim's last line...
don't guess...
i'm working it out
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2x+2=3
so far so good
then 2x=1
x=1/2?
x=.5
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yes, which is what in decimal form?
you got it
gnarly
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