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What is the derivative of f(x) = -sinx cox
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Use the product rule. \((fg)'(x)=f'(x)g(x)+f(x)g'(x)\).
I used that by somehow i do not get the right answer
Can you show your work?
-cosx(cosx)+ (-sinx)(-sinx)
-cox^2x- sin^2x am i right ??
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When you multiply those two (-sin x) terms together the minus signs cancel out, right?
Oh right i did not saw that , so it will become positve
Yep
Thank you i got it
Another trick is to notice \(f(x)=-\frac{1}{2}\sin 2x\), which is easier to differentiate.
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