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Mathematics 19 Online
OpenStudy (anonymous):

What is the derivative of f(x) = -sinx cox

OpenStudy (anonymous):

Use the product rule. \((fg)'(x)=f'(x)g(x)+f(x)g'(x)\).

OpenStudy (anonymous):

I used that by somehow i do not get the right answer

OpenStudy (anonymous):

Can you show your work?

OpenStudy (anonymous):

-cosx(cosx)+ (-sinx)(-sinx)

OpenStudy (anonymous):

-cox^2x- sin^2x am i right ??

OpenStudy (anonymous):

When you multiply those two (-sin x) terms together the minus signs cancel out, right?

OpenStudy (anonymous):

Oh right i did not saw that , so it will become positve

OpenStudy (anonymous):

Yep

OpenStudy (anonymous):

Thank you i got it

OpenStudy (anonymous):

Another trick is to notice \(f(x)=-\frac{1}{2}\sin 2x\), which is easier to differentiate.

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