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Define relations R and S on B as follows: R={(x,y) ∈ B x B|x^2+y^2=4} and S={(x,y) ∈ B x B|x=y}
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Graph R, S the union of R and S and the intersection of R and S
Are you given that B is? Or is it just some set?
R is circle x^2+y+2=4 S is the line x=y |dw:1338262081078:dw| Union is both the figures and intersection is
two points
hahah well its not really B it really is the Bold R but I didnt want to confuse u guys
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In that case, follow @NotSObright's advice.
Gotcha. Thanks that was great :)
Yes, \(\mathbb R \times \mathbb R\) is the two-dimensional plane.
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