For f(x)= -sinx, x= pi/4 determine the equation for the tangent to the curve at the point with the given x-coordinate

Question

For f(x)= -sinx,  x= pi/4 determine the equation for the tangent to the curve at the point with the given x-coordinate

anonymous · Answer

Substitute.$$f\left(\frac{\pi}{4}\right)=?$$

anonymous · Answer

the equation is y=-sin(x)

anonymous · Answer

? not quite sure what you mean by this question

nottim · Answer

maybe he was to look for the value of f(x) when x= pi/4?

anonymous · Answer

I need the derivative for f(x)= -sinx ... So that i can use y=mx+b to find the equation.

anonymous · Answer

What is the derivative of the sine function (something every calculus student must memorize!)?

nottim · Answer

isnt the derivative of -sin cosx?

nottim · Answer

oh shoot. i ruined that, srry yakey

anonymous · Answer

how'd you get cos(x) lol

anonymous · Answer

pull the negative out

$$-\frac{d}{dx}[\sin(x)]$$

nottim · Answer

aww. wrogn again huh

anonymous · Answer

yakey you should remember all your derivatives. It will help for when you get to integration

anonymous · Answer

or anti derivatives.... basicaly this is how you learn|dw:1338263885707:dw|