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Find the length of the side of the square 9x^2 + 6x + 1
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i assume that is the area?
Try factoring that.
factor it then get the square root
Yes the area
\[\Large s=\sqrt A=\sqrt{9x^2+6x+1}=\sqrt{(\cdots)^2}=\cdots\]
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I'm still not getting it?
Factor your polynomial like I suggested, and the answer will become obvious.
(3x+3) (3x-2) ?
I don't think I am factoring it correctly?
That's not correct...you can see that by FOILing that expression and seeing that it doesn't match the original. Try again.
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Hint: the two factors will be equal. (This is why it's a square)
So when you multiple them they equal 6 and when added they equal 1 ?
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