Question

Given the velocity is 48.76 m/s, how far would the object travel?

Answer 1

Picture to be posted...

Answer 2

i cant see the whole picture

Answer 3

pic is not so clear

Answer 4

So the original problem was this, but i found the velocity at the bottom of the loop after it completed a revolution. So the track it will travel from then on is 3m long with .3 value for friction.

Answer 5

What is the question? what is that circuit about? and those dotted lines .. and why do we need a motor?

Answer 6

Okay so a motor in a circuit pulls a 10 kg object on top of the track. It travels on the track until it collides with a 5kg object. They both travel through the loop together and moves with a constant velocity until it reaches the 3m section of the track where it has friction. Then it travels in a parabolic motion until it reaches the ground at point x.

Answer 7

The dotted lines between the two motors just show how they're the same. (:
The other one below it means that it's pulling the object upwards.
Sorry for the confusion --;;

Answer 8

I can see the path is something like a roller-coaster.. Isn't it?
Ok, since the figure is not very clear, can you tell me at what height from ground does the 10 kg object collide with 5 kg object? And at what height they begin the parabolic motion.. and what is the length of track with friction?

Answer 9

I found out everything that I need to know until the the point that says "3m". That's the length of the track with the friction. And the velocity when it reaches that point is 43.63m/s and is 10m above the ground. Also mew is .3 along the 3m track.

Answer 10

But the collision between the two objects occur 10m above the ground it travels a parabolic motion once it leaves the track, which is still 10m. The length of the track with friciton is 3m.

Answer 11

you have calculated the velocity of both object at the point they reach the track with friction. Right?

Answer 12

Yess

Answer 13

Ok, now can you calculate the frictional force on both bodies.. and hence the acceleration (deceleration, to be precise) for both the bodies...
Use these relations:\[F=\mu N\] and F=ma

Answer 14

Okay and then..

Answer 15

So is it 35.27m??

Answer 16

Sorry, i was a bit busy..

Answer 17

I don't know.. I haven't calculated..
But after you have found deceleration, find the value of final velocities with which the objects leave the track with friction.. They will be different for different objects..
That will be the velocities of projection for the objects which are now going to execute a parabolic motion..
I guess you can do it further..

Answer 18

Hehe okay. Thank you sooooo much!

Answer 19

Welcome..