I need to make this all one log function: 3logx−2log(x^2+1)+2log(x−1) i got: log((x^3)/(x^2+1)^2*(x-1)^2) but that's wrong.

Question

I need to make this all one log function:
3logx−2log(x^2+1)+2log(x−1)

i got:
log((x^3)/(x^2+1)^2*(x-1)^2)

but that's wrong. ><

anonymous · Answer

$$ 3\log x−2\log (x^2+1)+2 \log(x−1)  = \log \frac{x^3(x-1)^2}{(x^2+1)^2}$$

anonymous · Answer

i'm pretty sure I tried that as well as one of my options. we're allowed to answer this question as many times as we want. 
It didn't work. ><

anonymous · Answer

Do you know the answer?

anonymous · Answer

No, we aren't told it. It just says whether we're right or not.

anonymous · Answer

$$
3\log x - 2\log(x^2+1)+2\log(x-1)\
\log x^3-\log(x^2+1)^2+\log(x-1)^2\
\log\frac{x^3(x-1)^2}{(x^2+1)^2}
$$Same as FFM's solution.

anonymous · Answer

the problem then could be written wrong.  i don't see anything wrong with these solutions posted...

anonymous · Answer

yeah i dunno. i checked my working and stuff and did it again. 
but the system still called it wrong. 
it's okay. thanks though.