Lim f(x) = (x)/ (x^2 - x). It has discontinuities at;
a. nonremovable at x= 0
b. nonremovable at x = 0; removable at x = 1
c. removable at x = 0
d. removable at x=0 ; nonremovable at x = 1
e. the graoh is continuous for all real numbers

Question

Lim f(x) = (x)/ (x^2 - x). It has discontinuities at; 
a. nonremovable at x= 0
b. nonremovable at x = 0; removable at x = 1
c. removable at x = 0
d. removable at x=0 ; nonremovable at x = 1
e. the graoh is continuous for all real numbers

anonymous · Answer

see if you can remove a discontinuity by factoring and cancelling, because clearly this is undefined if $x=0$ or $x=1$

anonymous · Answer

oops, somehow my post got deleted, but i hope the answer was clear. you get 
$$f(x)=\frac{x}{x^2-x}=\frac{x}{x(x-1)}=\frac{1}{x-1} \text{ if } x\neq 0$$

anonymous · Answer

so zero is a removable discontinuity but 1 is not removable