Using euler's method how do I solve

y'= y - 2x
y_1 = 0

The step size is 0.5 (also could you tell me how to find this?)

Somehow my prof got

x_0 = 1
and
y_0 = 0

The two formulas I believe are

X_n = X_n-1 + h
Y_n = y_n-1 + h*f(x_n-1 - y_n-1)

Question

Using euler's method  how do I solve

y'= y - 2x
y_1 = 0

The step size is 0.5 (also could you tell me how to find this?)

Somehow my prof got

x_0 = 1
and
y_0 = 0

The two formulas I believe are

X_n = X_n-1 + h
Y_n = y_n-1 + h*f(x_n-1 - y_n-1)

australopithecus · Answer

note _ is used to denote subscript

experimentx · Answer

$$ y_{n+1} = y_n + h (y_n)'$$ http://en.wikipedia.org/wiki/Euler_method http://video.google.com/videoplay?docid=-547954516204762486

australopithecus · Answer

thanks

australopithecus · Answer

but there is no way you can quickly explain this so I dont have to sift through a lecture you dont have to answer it completely just tell me how to solve it :)

experimentx · Answer

increase x by adding h, h=0.5
calculate slope ... since you know y'
use that slope to find y for next step

again increase x by 0.5, since you know y from previous calculation
find y' ... since you know y and x 
calculate y for next next step ...

australopithecus · Answer

I will just watch the lecture thanks though.

experimentx · Answer

it's worth watching ... that funny professor!!

australopithecus · Answer

yeah he seems interesting lol

amistre64 · Answer

i do like my arthur mattuck  :)

experimentx · Answer

i like him too :)