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Mathematics 23 Online
OpenStudy (anonymous):

Use a unit circle and 30°–60°–90° triangles to find the value in degrees of each expression. cos^-1(1/2) please help

OpenStudy (apoorvk):

cos = base by height, right?

OpenStudy (anonymous):

yeah i guess i am so confused right now!

OpenStudy (apoorvk):

Don't be - calm down, it's just a stupid question :) so, what is angle 'X' when cosX= 1/2

OpenStudy (anonymous):

60 degrees?

OpenStudy (apoorvk):

Yes!! so, that's what cos^(-1)(1/2) would be!

OpenStudy (apoorvk):

Understanding this?

OpenStudy (anonymous):

so the anwser is really 60 degrees? and not really can you help with a few more?

OpenStudy (anonymous):

tan^-1(1/squareroot3)

OpenStudy (apoorvk):

Okay same funda - what is 'X' when tanX = 1/sqrt3??

OpenStudy (apoorvk):

Yeah the answer is 60 degrees actually! (for the first one)

OpenStudy (anonymous):

is it 45 degrees?

OpenStudy (apoorvk):

Nope. tan45 =1 remember?

OpenStudy (anonymous):

idk then?

OpenStudy (anonymous):

oh its 30 degrees

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