Solve: x^2− 2x − 24 = 0. A. x = 4, x = 6 B. x = 4, x = −6 C. x = −4, x = 6 D. x = −4, x = −6
Use the quadratic formula to solve.
\(\Large \color{Black}{\Rightarrow x = {-b \pm \sqrt{b^2 - 4ac} \over 2a} }\)
Can't you also factor and then solve? So you would get (x-6)(x+4)? And then you set them both equal to zero like this? (x-6)=0 and (x+4)=0, so your answers would be x=6 and x=-4??
Eeky @iheartfood
You shouldn't be giving the complete answer
What do you mean by eeky? hahaa oh oops my bad.. should i delete that post then??
@ParthKohli should i delete the answer then?
No, too late now :P
aww man!! sorry!! i didn't' know!! my bad...... but was my way okay too @ParthKohli ??
Yeah, factoring is a very good way to solve ^_^
yay!! :)
I used to solve them by factoring, but now I see that the formula is convenient.
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