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integral of e^x+lnx^2dx
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I mean \[\int\limits_{}^{} e^{x+lnx^2}dx\]
Integration by parts
u=x^2 dv=e^xdx du=2xdx v=e^x \[e^x x^2-2\int\limits e^x x \, dx \]
By parts again u=x dv=e^x du=dx v=e^x
\[e^x x^2-2 e^x x+2\int\limits e^x \, dx \]
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Solve can simplify
I mean and*
how do we decide u and dv in general :(
Its integration by parts, you must let u=x^2 NOT u=e^x because when you differentiate u=x^2, it will get smaller and smaller. but if you take u=e^x then when you differentiate it it's still the same, and you'll get infinite loop
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