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y=-.029x^2+.286x+1.093. find the x-intercepts
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@miss2ne2 do you know what is x-intercept?
yes but i just cant remember how to get the answers. they are suppose to be 1987 and 2003 but i just cant seem to get those answers
X-intercept is/ are the points where the curve crosses x-axis or y=0
yes i know
so put y=0 and then solve for x!!
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so how would i do that?
Do you know the quadratic formula?
yes thats how i set it up but yet i know i did something wrong.
Show your approach here, I'll guide you if I find any mistake:)
\[-.286\pm \sqrt{?}.286^2-4(-.029)(1.093)\div2(-.029)\]
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never mind i just figured it out. i saw that i was adding somethings wrong. thanks for your help.
Are you sure? let me know if you need help
yes i am sure. and thanks again..
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