Question

how would you find the vertex of the parabola ? x^2-6x+8=y

Answer 1

Complete the square.
x^2 - 6x = y - 8
x^2 - 6x + 9 = y + 1
(x - 3)^2 = y + 1
(x - 3)^2 - 1 = y

So, the vertex is (3,1)

Answer 2

You add (b/2)^2 to both sides.

Answer 3

first coordinate of vertex is always \(-\frac{b}{2a}\)
in your case it is \(-\frac{-6}{2}=3\)
second coordinate is what you get when you replace \(x\) by 3
in this case you get \(3^2-6\times 3+8=9-18+8=-9+8=-1\)

Answer 4

and so vertex it \((3,-1)\)

Answer 5

Oh no

Answer 6

@satellite73 check out my smartscore hehe

Answer 7

way to go!

Answer 8

thanks!

Answer 9

38 days

Answer 10

amazing
don't you ever sleep? must be a friend of saifoo

Answer 11

Lol no I'm not saifoo's friend...and I didn't sleep last night

Answer 12

btw vertex is still \((3,-1)\)

Answer 13

your next job is to learn \(\LaTeX\) so you can write up answers nice nice

Answer 14

I know Latex.

Answer 15

oh ok

Answer 16

\(\Huge \color{Green}{\text{Here we go, satellite73.}}\)

Answer 17

lol

Answer 18

;) your mom is from Palestine right?