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OpenStudy (anonymous):
the square root of 32y to the 7 power
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jhonyy9 (jhonyy9):
so squareroot sign exponent 1/2 --- yes ?
jhonyy9 (jhonyy9):
32 is 2 on exponent 5
jhonyy9 (jhonyy9):
and y is on exponent 7
jhonyy9 (jhonyy9):
so (a^b)^c = ???
jhonyy9 (jhonyy9):
so than there is (2^5 *y^7 )^(1/2)
- how many will be this ?
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OpenStudy (anonymous):
omg i have no idea i dont even know how to read that
jhonyy9 (jhonyy9):
so if there is sqrt(x^a) =(x^a)^(1/2) =x^(a *(1/2)) =x^(a/2)
can you using this example in your exercise ?
OpenStudy (anonymous):
they give 4y^3 square root 2y
9
3y square root of 2
2y^3 square root of 2y
jhonyy9 (jhonyy9):
how do you think what will be right ?
jhonyy9 (jhonyy9):
if you replace 4 inside squaroot how many will be ?
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jhonyy9 (jhonyy9):
will be 4 squared =4^2 = 4*4 = ?
jhonyy9 (jhonyy9):
so you have wrote : they give ...
jhonyy9 (jhonyy9):
check these answers for you can giving the right answer
jhonyy9 (jhonyy9):
32 =2^5 =2^4 *2
but you know that 2^4 inside squaroot = 2^2 so than sqrt(2^5) = sqrt(2^4 *2) =
=2^2 *sqrt2 =4sqrt2
ok ?
jhonyy9 (jhonyy9):
came on
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OpenStudy (anonymous):
ooooooh lol okay thanks i got it
jhonyy9 (jhonyy9):
good luck
bye
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