Please help me condense the following logarithm:
(1/5)[log2 f + 3log2 g] - log2(3) - 6log2 (h-11)

Thanks!!

Question

Please help me condense the following logarithm:
(1/5)[log2 f + 3log2 g] - log2(3) - 6log2 (h-11)

Thanks!!

anonymous · Answer

This item has common base of log2

cwrw238 · Answer

use laws of logs
log a + log b = log ab
log a - log b = log a/b
n log a = log a^n

ill start you off:
log2 f + 3 log2 g
= log2 f + log2 g^3
= log2 fg^3

anonymous · Answer

i've gotten that far.  I just don't understand how.  I have the rules but can't seem to condensed or expand properly.

cwrw238 · Answer

well next thing to do is change (1/5) log2 fg^3  - using the 3rd law of logs shown above

- this is a sticky one i must admit,  next apply 3rd law to the last term and then the 2nd law to last two terms

anonymous · Answer

$$z \le \log43+3\log6/2\log6??$$

anonymous · Answer

is this correct?

mertsj · Answer

Do you need help with this problem?