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HELP ME PLEASE! Simplify the following expression show all of your work: x/x-4 + 6/x+4 ÷ 3/2x^2 - 32
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Can someone please help me i really need help
\[(\frac{x}{x-4} + \frac{6}{x+4}) ÷ \frac{ 3}{2x^2 - 32}\]\[=(\frac{x(x+4)}{(x-4)(x+4)} + \frac{6(x-4)}{(x+4)(x-4)}) ÷ \frac{ 3}{2(x^2 - 16)}\]\[=\frac{x^2+4x+6x-24}{(x-4)(x+4)} ÷ \frac{ 3}{2(x-4)(x+4)}\]\[=\frac{(x+12)(x-2)}{(x-4)(x+4)} \times \frac{2(x-4)(x+4)}{ 3}\]Now, can you cancel the common factors to simplify the expression?
2x^2 + 20x - 48/3
Oh... if you need to expand the term, then that's it!~
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