If y=4(1.6)^x , what is the approximate value of x when y = 12?
Answer
a. 2.1
b. 1.9
c. 2.5
d. 2.3

Question

If y=4(1.6)^x , what is the approximate value of x when y = 12?
Answer
	 a.	2.1
	 b.	1.9
	 c.	2.5
	 d.	2.3

callisto · Answer

y=4(1.6)^x and y =12
12 = 4(1.6)^x
3=1.6^x
xlog(1.6) = log3
x = log3 / log1.6 =?

anonymous · Answer

b?

callisto · Answer

Nope :|

anonymous · Answer

thats what i got when i typed it in what u get?

callisto · Answer

x=(log3) / (log1.6)

anonymous · Answer

just plug the answers they gave you in for x and when you get 12 as your answer, that is the x....does that make sense

anonymous · Answer

12=4(1.6)^x
	 a.	2.1=x
	 b.	1.9=x
	 c.	2.5=x
	 d.	2.3=x

anonymous · Answer

so C

anonymous · Answer

so which is it one of your answers is c and the others is d

callisto · Answer

Actually, instead of putting the value into the equation provided, you can solve it :|

anonymous · Answer

either way, that's what i do on tests...just so i make sure i get the right answer...ha sorry if i made more work for you :/