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ugh i cant do this :'(
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U can choose more then 1
You substitute each value for t in the equation. Take t=0 for example. \[d(0)=16+5(0)-0^2=16\] So t=0 works. Do that for the rest.
I feel like nothing else works but zero just by looking at it
o no d works as well
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SO A and D?
Yep, just those two.
write it in standard form and factor the expression : 16 = 16 + 5t - t^2
yep u were right thanks :)
Sure thing :)
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