What are the x– and y–intercepts of the quadratic equation y = 2x2 – 8x + 6?
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OpenStudy (anonymous):
For the y-intercept, plug in 0 for x.
For the x-intercepts, plug in zero for y and factor it.
OpenStudy (amorfide):
factorise to get x
factorising gives
2x2 -6x-2x+6
2x(x-3)-2(x-3)
(2x-2)(x-3)
x=2/3
or
x=3
sub both into the original equation to get 2 y values
this gives two coordinates
OpenStudy (anonymous):
0 = 2(x^2 - 4x + 3)
0 = (x - 3)(x - 1)
x = 3 and 1.
OpenStudy (amorfide):
yeah you are right
i got 2/2 not 2/3 lol
OpenStudy (anonymous):
Therefore, the y-intercept is 6. (0, 6)
The x-intercepts are 3 and 1. (3, 0) (1, 0)
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OpenStudy (anonymous):
for the answer choices there is no y-intercept that =-6
OpenStudy (anonymous):
I changes it
OpenStudy (anonymous):
i see now lol.
OpenStudy (anonymous):
can you help me on another one?
OpenStudy (anonymous):
Sure
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OpenStudy (anonymous):
Describe the differences between the graph of y= -3/4(x-6)^2+4 and the standard position graph of y = x^2.
OpenStudy (anonymous):
Wait, are you in algebra I or algebra II? THat way I know how in depth I should go.