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The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.
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area of the triangle = sqrt(18*(18-12)^3) = 62.354 sq ins so this is also the area of the hexagon so whats the next step?
area of hexagon = 3*sqrt3 * t^2 ------- 2
so equate this to 62.354 and solve for t (t = length of each side of the hexagon)
ok ? any questions?
No thx
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i used heros formula for finding area of triangle Area = sqrt [(s(s-a)(s-b)(s-c)] where a,b and c are lengths of 3 sides and s = half of perimeter
ok
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