Question

What is the vertex of the function y=x^2-4x+3 ? Use the Equation Editor to write your answer as an ordered pair. (Hint: you will want to find the axis of symmetry first).

Answer 1

no agony to find the vertex.
first coordinate of the vertex is always \(-\frac{b}{2a}\) in this case it is \(-\frac{-4}{2}=2\)
to find the second coordinate of the vertex, replace \(x\) by 2 and get
\[y=2^2-4\times 2+3=4-8+3=-4+3=-1\]

Answer 2

and therefore your vertex is \((2,-1)\)

Answer 3

lol i dont have one xD

Answer 4

lol